Base | Representation |
---|---|
bin | 101001010110101111… |
… | …101101101011100101 |
3 | 11020121122212210212201 |
4 | 221112233231223211 |
5 | 1211420141141123 |
6 | 32222133414501 |
7 | 3131253311554 |
oct | 512657555345 |
9 | 136548783781 |
10 | 44405021413 |
11 | 17917527905 |
12 | 873319a431 |
13 | 4258882ccc |
14 | 2213631d9b |
15 | 124d5b35ad |
hex | a56bedae5 |
44405021413 has 2 divisors, whose sum is σ = 44405021414. Its totient is φ = 44405021412.
The previous prime is 44405021387. The next prime is 44405021443. The reversal of 44405021413 is 31412050444.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 42581560609 + 1823460804 = 206353^2 + 42702^2 .
It is a cyclic number.
It is not a de Polignac number, because 44405021413 - 221 = 44402924261 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (44405021443) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 22202510706 + 22202510707.
It is an arithmetic number, because the mean of its divisors is an integer number (22202510707).
Almost surely, 244405021413 is an apocalyptic number.
It is an amenable number.
44405021413 is a deficient number, since it is larger than the sum of its proper divisors (1).
44405021413 is an equidigital number, since it uses as much as digits as its factorization.
44405021413 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 7680, while the sum is 28.
Adding to 44405021413 its reverse (31412050444), we get a palindrome (75817071857).
The spelling of 44405021413 in words is "forty-four billion, four hundred five million, twenty-one thousand, four hundred thirteen".
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