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444130121 is a prime number
BaseRepresentation
bin11010011110001…
…110001101001001
31010221201010222202
4122132032031021
51402144130441
6112023125545
714002021001
oct3236161511
91127633882
10444130121
11208777596
121048a38b5
1371022cb6
1442db1001
1528ece19b
hex1a78e349

444130121 has 2 divisors, whose sum is σ = 444130122. Its totient is φ = 444130120.

The previous prime is 444130079. The next prime is 444130123. The reversal of 444130121 is 121031444.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 229946896 + 214183225 = 15164^2 + 14635^2 .

It is a cyclic number.

It is not a de Polignac number, because 444130121 - 214 = 444113737 is a prime.

Together with 444130123, it forms a pair of twin primes.

It is a Chen prime.

It is a junction number, because it is equal to n+sod(n) for n = 444130093 and 444130102.

It is not a weakly prime, because it can be changed into another prime (444130123) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 222065060 + 222065061.

It is an arithmetic number, because the mean of its divisors is an integer number (222065061).

Almost surely, 2444130121 is an apocalyptic number.

It is an amenable number.

444130121 is a deficient number, since it is larger than the sum of its proper divisors (1).

444130121 is an equidigital number, since it uses as much as digits as its factorization.

444130121 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 384, while the sum is 20.

The square root of 444130121 is about 21074.3949142081. The cubic root of 444130121 is about 762.9628806791.

Adding to 444130121 its reverse (121031444), we get a palindrome (565161565).

The spelling of 444130121 in words is "four hundred forty-four million, one hundred thirty thousand, one hundred twenty-one".