Base | Representation |
---|---|
bin | 101001010111001110… |
… | …101010100100100101 |
3 | 11020122020011000211011 |
4 | 221113032222210211 |
5 | 1211424230311031 |
6 | 32223023342221 |
7 | 3131412264004 |
oct | 512716524445 |
9 | 136566130734 |
10 | 44413135141 |
11 | 17921069871 |
12 | 8735a51971 |
13 | 425a46412b |
14 | 2214744c3b |
15 | 124e1676b1 |
hex | a573aa925 |
44413135141 has 2 divisors, whose sum is σ = 44413135142. Its totient is φ = 44413135140.
The previous prime is 44413135121. The next prime is 44413135147. The reversal of 44413135141 is 14153131444.
44413135141 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 23006519041 + 21406616100 = 151679^2 + 146310^2 .
It is a cyclic number.
It is not a de Polignac number, because 44413135141 - 213 = 44413126949 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (44413135147) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 22206567570 + 22206567571.
It is an arithmetic number, because the mean of its divisors is an integer number (22206567571).
Almost surely, 244413135141 is an apocalyptic number.
It is an amenable number.
44413135141 is a deficient number, since it is larger than the sum of its proper divisors (1).
44413135141 is an equidigital number, since it uses as much as digits as its factorization.
44413135141 is an evil number, because the sum of its binary digits is even.
The product of its digits is 11520, while the sum is 31.
Adding to 44413135141 its reverse (14153131444), we get a palindrome (58566266585).
The spelling of 44413135141 in words is "forty-four billion, four hundred thirteen million, one hundred thirty-five thousand, one hundred forty-one".
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