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44413355331444 = 223114773137715811
BaseRepresentation
bin10100001100100110010100…
…10001001000111101110100
312211020212122002121012210210
422012103022101020331310
521310132022431101234
6234243114101345420
712232521230306211
oct1206231221107564
9184225562535723
1044413355331444
111317366425a240
124b93732a08270
131ba22138a4cc8
14ad7891600b08
1552045ed10be9
hex2864ca448f74

44413355331444 has 192 divisors, whose sum is σ = 117893617938432. Its totient is φ = 12896949196800.

The previous prime is 44413355331437. The next prime is 44413355331461.

44413355331444 is nontrivially palindromic in base 10.

It is a super-2 number, since 2×444133553314442 (a number of 28 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 44413355331393 and 44413355331402.

It is a congruent number.

It is an unprimeable number.

It is a polite number, since it can be written in 63 ways as a sum of consecutive naturals, for example, 61688299 + ... + 62404109.

It is an arithmetic number, because the mean of its divisors is an integer number (614029260096).

Almost surely, 244413355331444 is an apocalyptic number.

44413355331444 is a gapful number since it is divisible by the number (44) formed by its first and last digit.

It is an amenable number.

It is a practical number, because each smaller number is the sum of distinct divisors of 44413355331444, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (58946808969216).

44413355331444 is an abundant number, since it is smaller than the sum of its proper divisors (73480262606988).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

44413355331444 is a wasteful number, since it uses less digits than its factorization.

44413355331444 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 716086 (or 716084 counting only the distinct ones).

The product of its digits is 8294400, while the sum is 48.

It can be divided in two parts, 4441335 and 5331444, that added together give a palindrome (9772779).

The spelling of 44413355331444 in words is "forty-four trillion, four hundred thirteen billion, three hundred fifty-five million, three hundred thirty-one thousand, four hundred forty-four".