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44420013331 is a prime number
BaseRepresentation
bin101001010111101000…
…111001110100010011
311020122201002110220221
4221113220321310103
51211433010411311
632223431013511
73131524612021
oct512750716423
9136581073827
1044420013331
1117924a37521
12873820a297
13425ba01a75
142215615711
15124ea75671
hexa57a39d13

44420013331 has 2 divisors, whose sum is σ = 44420013332. Its totient is φ = 44420013330.

The previous prime is 44420013317. The next prime is 44420013353. The reversal of 44420013331 is 13331002444.

It is a weak prime.

It is a cyclic number.

It is not a de Polignac number, because 44420013331 - 27 = 44420013203 is a prime.

It is a super-2 number, since 2×444200133312 (a number of 22 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 44420013296 and 44420013305.

It is not a weakly prime, because it can be changed into another prime (44420013311) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 22210006665 + 22210006666.

It is an arithmetic number, because the mean of its divisors is an integer number (22210006666).

Almost surely, 244420013331 is an apocalyptic number.

44420013331 is a deficient number, since it is larger than the sum of its proper divisors (1).

44420013331 is an equidigital number, since it uses as much as digits as its factorization.

44420013331 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 3456, while the sum is 25.

Adding to 44420013331 its reverse (13331002444), we get a palindrome (57751015775).

The spelling of 44420013331 in words is "forty-four billion, four hundred twenty million, thirteen thousand, three hundred thirty-one".