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444300110300041 is a prime number
BaseRepresentation
bin110010100000101101010111…
…0001111111000001110001001
32011021010200020121100200100021
41211001122232033320032021
5431213403111214100131
64212540353010340441
7162404423630326252
oct14501325617701611
92137120217320307
10444300110300041
11119627689425696
12419b8407b8a721
13160bb42254b628
147ba0350ab7b29
1536573eb000e11
hex19416ae3f8389

444300110300041 has 2 divisors, whose sum is σ = 444300110300042. Its totient is φ = 444300110300040.

The previous prime is 444300110300029. The next prime is 444300110300119. The reversal of 444300110300041 is 140003011003444.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 383272828796025 + 61027281504016 = 19577355^2 + 7811996^2 .

It is a cyclic number.

It is not a de Polignac number, because 444300110300041 - 221 = 444300108202889 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 444300110299979 and 444300110300015.

It is not a weakly prime, because it can be changed into another prime (444300110301041) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 222150055150020 + 222150055150021.

It is an arithmetic number, because the mean of its divisors is an integer number (222150055150021).

Almost surely, 2444300110300041 is an apocalyptic number.

It is an amenable number.

444300110300041 is a deficient number, since it is larger than the sum of its proper divisors (1).

444300110300041 is an equidigital number, since it uses as much as digits as its factorization.

444300110300041 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 2304, while the sum is 25.

Adding to 444300110300041 its reverse (140003011003444), we get a palindrome (584303121303485).

The spelling of 444300110300041 in words is "four hundred forty-four trillion, three hundred billion, one hundred ten million, three hundred thousand, forty-one".