Base | Representation |
---|---|
bin | 100000010101100011011… |
… | …0110110010001100101011 |
3 | 120201212121011120001220002 |
4 | 1000223012312302030223 |
5 | 1040303443100343334 |
6 | 13241410444053215 |
7 | 636043462245356 |
oct | 100530666621453 |
9 | 16655534501802 |
10 | 4444332434219 |
11 | 1463915882a57 |
12 | 5b9411b3420b |
13 | 263138c53772 |
14 | 11516d23b29d |
15 | 7a9198c9b7e |
hex | 40ac6db232b |
4444332434219 has 2 divisors, whose sum is σ = 4444332434220. Its totient is φ = 4444332434218.
The previous prime is 4444332434209. The next prime is 4444332434257. The reversal of 4444332434219 is 9124342334444.
4444332434219 is digitally balanced in base 3, because in such base it contains all the possibile digits an equal number of times.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 4444332434219 - 232 = 4440037466923 is a prime.
It is a super-2 number, since 2×44443324342192 (a number of 26 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (4444332434209) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2222166217109 + 2222166217110.
It is an arithmetic number, because the mean of its divisors is an integer number (2222166217110).
Almost surely, 24444332434219 is an apocalyptic number.
4444332434219 is a deficient number, since it is larger than the sum of its proper divisors (1).
4444332434219 is an equidigital number, since it uses as much as digits as its factorization.
4444332434219 is an evil number, because the sum of its binary digits is even.
The product of its digits is 3981312, while the sum is 47.
The spelling of 4444332434219 in words is "four trillion, four hundred forty-four billion, three hundred thirty-two million, four hundred thirty-four thousand, two hundred nineteen".
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