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4446389982017 is a prime number
BaseRepresentation
bin100000010110100000101…
…1111101101001101000001
3120202001220120012022212002
41000231001133231031001
51040322201313411032
613242350544313345
7636145455152114
oct100550137551501
916661816168762
104446389982017
111464781256085
125b98a7012855
132633a62c9879
141152c65d657b
157a9da358862
hex40b417ed341

4446389982017 has 2 divisors, whose sum is σ = 4446389982018. Its totient is φ = 4446389982016.

The previous prime is 4446389981899. The next prime is 4446389982019. The reversal of 4446389982017 is 7102899836444.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 4187114507536 + 259275474481 = 2046244^2 + 509191^2 .

It is a cyclic number.

It is not a de Polignac number, because 4446389982017 - 242 = 48343470913 is a prime.

It is a super-2 number, since 2×44463899820172 (a number of 26 digits) contains 22 as substring.

Together with 4446389982019, it forms a pair of twin primes.

It is a Chen prime.

It is not a weakly prime, because it can be changed into another prime (4446389982019) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2223194991008 + 2223194991009.

It is an arithmetic number, because the mean of its divisors is an integer number (2223194991009).

Almost surely, 24446389982017 is an apocalyptic number.

It is an amenable number.

4446389982017 is a deficient number, since it is larger than the sum of its proper divisors (1).

4446389982017 is an equidigital number, since it uses as much as digits as its factorization.

4446389982017 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 83607552, while the sum is 65.

The spelling of 4446389982017 in words is "four trillion, four hundred forty-six billion, three hundred eighty-nine million, nine hundred eighty-two thousand, seventeen".