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4463135121131 is a prime number
BaseRepresentation
bin100000011110010011110…
…0101010101111011101011
3120210200010120010112100122
41000330213211111323223
51041111000042334011
613254200322553455
7640310435404511
oct100744745257353
916720116115318
104463135121131
111470894470a25
12600b9ab0888b
13264b44567bcb
141160344d24b1
157b16a48b3db
hex40f27955eeb

4463135121131 has 2 divisors, whose sum is σ = 4463135121132. Its totient is φ = 4463135121130.

The previous prime is 4463135121089. The next prime is 4463135121197. The reversal of 4463135121131 is 1311215313644.

It is a happy number.

It is a weak prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-4463135121131 is a prime.

It is a super-2 number, since 2×44631351211312 (a number of 26 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 4463135121091 and 4463135121100.

It is not a weakly prime, because it can be changed into another prime (4463135121031) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2231567560565 + 2231567560566.

It is an arithmetic number, because the mean of its divisors is an integer number (2231567560566).

Almost surely, 24463135121131 is an apocalyptic number.

4463135121131 is a deficient number, since it is larger than the sum of its proper divisors (1).

4463135121131 is an equidigital number, since it uses as much as digits as its factorization.

4463135121131 is an evil number, because the sum of its binary digits is even.

The product of its digits is 25920, while the sum is 35.

The spelling of 4463135121131 in words is "four trillion, four hundred sixty-three billion, one hundred thirty-five million, one hundred twenty-one thousand, one hundred thirty-one".