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449413971319 is a prime number
BaseRepresentation
bin1101000101000110010…
…10001111110101110111
31120222000102200012101201
412202203022033311313
524330344434040234
6542242525033331
744316616504225
oct6424312176567
91528012605351
10449413971319
1116366051a425
12731239b5847
13334c1b64821
1417a74b45b15
15ba54ad0314
hex68a328fd77

449413971319 has 2 divisors, whose sum is σ = 449413971320. Its totient is φ = 449413971318.

The previous prime is 449413971151. The next prime is 449413971341. The reversal of 449413971319 is 913179314944.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 449413971319 - 219 = 449413447031 is a prime.

It is a super-2 number, since 2×4494139713192 (a number of 24 digits) contains 22 as substring.

It is a self number, because there is not a number n which added to its sum of digits gives 449413971319.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (449413971379) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 224706985659 + 224706985660.

It is an arithmetic number, because the mean of its divisors is an integer number (224706985660).

Almost surely, 2449413971319 is an apocalyptic number.

449413971319 is a deficient number, since it is larger than the sum of its proper divisors (1).

449413971319 is an equidigital number, since it uses as much as digits as its factorization.

449413971319 is an evil number, because the sum of its binary digits is even.

The product of its digits is 2939328, while the sum is 55.

The spelling of 449413971319 in words is "four hundred forty-nine billion, four hundred thirteen million, nine hundred seventy-one thousand, three hundred nineteen".