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44944911953 is a prime number
BaseRepresentation
bin101001110110111011…
…001110111001010001
311022000021210002110122
4221312323032321101
51214021344140303
632351501240025
73150530306504
oct516673167121
9138007702418
1044944911953
111807425a637
128863b63015
134313693b76
14226520d13b
151280baae38
hexa76ecee51

44944911953 has 2 divisors, whose sum is σ = 44944911954. Its totient is φ = 44944911952.

The previous prime is 44944911941. The next prime is 44944911983. The reversal of 44944911953 is 35911944944.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 44393225809 + 551686144 = 210697^2 + 23488^2 .

It is a cyclic number.

It is not a de Polignac number, because 44944911953 - 26 = 44944911889 is a prime.

It is a super-2 number, since 2×449449119532 (a number of 22 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 44944911895 and 44944911904.

It is not a weakly prime, because it can be changed into another prime (44944911983) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 22472455976 + 22472455977.

It is an arithmetic number, because the mean of its divisors is an integer number (22472455977).

Almost surely, 244944911953 is an apocalyptic number.

It is an amenable number.

44944911953 is a deficient number, since it is larger than the sum of its proper divisors (1).

44944911953 is an equidigital number, since it uses as much as digits as its factorization.

44944911953 is an odious number, because the sum of its binary digits is odd.

The product of its digits is 2799360, while the sum is 53.

The spelling of 44944911953 in words is "forty-four billion, nine hundred forty-four million, nine hundred eleven thousand, nine hundred fifty-three".