4500341300125 has 32 divisors (see below), whose sum is σ = 6127322557824. Its totient is φ = 3272808592000.

The previous prime is 4500341300089. The next prime is 4500341300309. The reversal of 4500341300125 is 5210031430054.

It is not a de Polignac number, because 4500341300125 - 2³¹ = 4498193816477 is a prime.

It is a super-2 number, since 2×4500341300125² (a number of 26 digits) contains 22 as substring.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 4500341300093 and 4500341300102.

It is a congruent number.

It is an unprimeable number.

It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 31136274 + ... + 31280476.

It is an arithmetic number, because the mean of its divisors is an integer number (191478829932).

Almost surely, 2^{4500341300125} is an apocalyptic number.

It is an amenable number.

4500341300125 is a deficient number, since it is larger than the sum of its proper divisors (1626981257699).

4500341300125 is a wasteful number, since it uses less digits than its factorization.

4500341300125 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 166926 (or 166916 counting only the distinct ones).

The product of its (nonzero) digits is 7200, while the sum is 28.

Adding to 4500341300125 its reverse (5210031430054), we get a palindrome (9710372730179).

The spelling of 4500341300125 in words is "four trillion, five hundred billion, three hundred forty-one million, three hundred thousand, one hundred twenty-five".