Base | Representation |
---|---|
bin | 1101001000001001100… |
… | …10111001001000000011 |
3 | 1121010020120221111110002 |
4 | 12210010302321020003 |
5 | 24342223304004011 |
6 | 543113242030215 |
7 | 44405326610123 |
oct | 6440462711003 |
9 | 1533216844402 |
10 | 451052016131 |
11 | 164321116772 |
12 | 735004a836b |
13 | 336c332b202 |
14 | 17b8c500c83 |
15 | baed7e6c3b |
hex | 6904cb9203 |
451052016131 has 2 divisors, whose sum is σ = 451052016132. Its totient is φ = 451052016130.
The previous prime is 451052016101. The next prime is 451052016133. The reversal of 451052016131 is 131610250154.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 451052016131 - 218 = 451051753987 is a prime.
It is a super-2 number, since 2×4510520161312 (a number of 24 digits) contains 22 as substring.
Together with 451052016133, it forms a pair of twin primes.
It is a Chen prime.
It is a junction number, because it is equal to n+sod(n) for n = 451052016094 and 451052016103.
It is not a weakly prime, because it can be changed into another prime (451052016133) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 225526008065 + 225526008066.
It is an arithmetic number, because the mean of its divisors is an integer number (225526008066).
Almost surely, 2451052016131 is an apocalyptic number.
451052016131 is a deficient number, since it is larger than the sum of its proper divisors (1).
451052016131 is an equidigital number, since it uses as much as digits as its factorization.
451052016131 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 3600, while the sum is 29.
Adding to 451052016131 its reverse (131610250154), we get a palindrome (582662266285).
The spelling of 451052016131 in words is "four hundred fifty-one billion, fifty-two million, sixteen thousand, one hundred thirty-one".
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