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451222474117 is a prime number
BaseRepresentation
bin1101001000011101111…
…01001000110110000101
31121010200110200122211211
412210032331020312011
524343100423132432
6543142211331421
744412466514152
oct6441675106605
91533613618754
10451222474117
111643a9361338
12735495b0b71
133371c740b1c
1417ba6dd3229
15bb0d767d47
hex690ef48d85

451222474117 has 2 divisors, whose sum is σ = 451222474118. Its totient is φ = 451222474116.

The previous prime is 451222474103. The next prime is 451222474127. The reversal of 451222474117 is 711474222154.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 313867737121 + 137354736996 = 560239^2 + 370614^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-451222474117 is a prime.

It is a super-2 number, since 2×4512224741172 (a number of 24 digits) contains 22 as substring.

It is a self number, because there is not a number n which added to its sum of digits gives 451222474117.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (451222474127) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 225611237058 + 225611237059.

It is an arithmetic number, because the mean of its divisors is an integer number (225611237059).

Almost surely, 2451222474117 is an apocalyptic number.

It is an amenable number.

451222474117 is a deficient number, since it is larger than the sum of its proper divisors (1).

451222474117 is an equidigital number, since it uses as much as digits as its factorization.

451222474117 is an odious number, because the sum of its binary digits is odd.

The product of its digits is 125440, while the sum is 40.

The spelling of 451222474117 in words is "four hundred fifty-one billion, two hundred twenty-two million, four hundred seventy-four thousand, one hundred seventeen".