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45205314025301 is a prime number
BaseRepresentation
bin10100100011101001011101…
…01011110011011101010101
312221001120211001121021111222
422101310232223303131111
521411120440342302201
6240051011244540125
712343655552163053
oct1221645653633525
9187046731537458
1045205314025301
11134495142a3681
1250a1114251645
131c2bac58a8361
14b23d3d9c91d3
15535d6219891b
hex291d2eaf3755

45205314025301 has 2 divisors, whose sum is σ = 45205314025302. Its totient is φ = 45205314025300.

The previous prime is 45205314025243. The next prime is 45205314025337. The reversal of 45205314025301 is 10352041350254.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 38171069619076 + 7034244406225 = 6178274^2 + 2652215^2 .

It is a cyclic number.

It is not a de Polignac number, because 45205314025301 - 218 = 45205313763157 is a prime.

It is a super-2 number, since 2×452053140253012 (a number of 28 digits) contains 22 as substring.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (45205314025901) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 22602657012650 + 22602657012651.

It is an arithmetic number, because the mean of its divisors is an integer number (22602657012651).

Almost surely, 245205314025301 is an apocalyptic number.

It is an amenable number.

45205314025301 is a deficient number, since it is larger than the sum of its proper divisors (1).

45205314025301 is an equidigital number, since it uses as much as digits as its factorization.

45205314025301 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 72000, while the sum is 35.

Adding to 45205314025301 its reverse (10352041350254), we get a palindrome (55557355375555).

The spelling of 45205314025301 in words is "forty-five trillion, two hundred five billion, three hundred fourteen million, twenty-five thousand, three hundred one".