Base | Representation |
---|---|
bin | 10100100101000011010000… |
… | …10000001100111010010011 |
3 | 12221020012020221010120022122 |
4 | 22102201220100030322103 |
5 | 21412413204233231212 |
6 | 240125103202524455 |
7 | 12350313344422103 |
oct | 1222415020147223 |
9 | 187205227116278 |
10 | 45253524508307 |
11 | 13467a03912065 |
12 | 50aa52996672b |
13 | 1c3350998868b |
14 | b263d47b1203 |
15 | 5372348a6272 |
hex | 29286840ce93 |
45253524508307 has 2 divisors, whose sum is σ = 45253524508308. Its totient is φ = 45253524508306.
The previous prime is 45253524508271. The next prime is 45253524508349. The reversal of 45253524508307 is 70380542535254.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 45253524508307 - 222 = 45253520314003 is a prime.
It is a super-2 number, since 2×452535245083072 (a number of 28 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (45253524508397) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 22626762254153 + 22626762254154.
It is an arithmetic number, because the mean of its divisors is an integer number (22626762254154).
Almost surely, 245253524508307 is an apocalyptic number.
45253524508307 is a deficient number, since it is larger than the sum of its proper divisors (1).
45253524508307 is an equidigital number, since it uses as much as digits as its factorization.
45253524508307 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 20160000, while the sum is 53.
The spelling of 45253524508307 in words is "forty-five trillion, two hundred fifty-three billion, five hundred twenty-four million, five hundred eight thousand, three hundred seven".
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