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4530513234131 is a prime number
BaseRepresentation
bin100000111101101011110…
…1000011100100011010011
3121001010001020221022102022
41001323113220130203103
51043211442341443011
613345142233442055
7645214225044653
oct101732750344323
917033036838368
104530513234131
11149741a679535
1261206387032b
1326b2c1748321
141193c6c0a363
157ccb07e68db
hex41ed7a1c8d3

4530513234131 has 2 divisors, whose sum is σ = 4530513234132. Its totient is φ = 4530513234130.

The previous prime is 4530513234119. The next prime is 4530513234133. The reversal of 4530513234131 is 1314323150354.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 4530513234131 - 26 = 4530513234067 is a prime.

It is a super-2 number, since 2×45305132341312 (a number of 26 digits) contains 22 as substring.

Together with 4530513234133, it forms a pair of twin primes.

It is a Chen prime.

It is a junction number, because it is equal to n+sod(n) for n = 4530513234091 and 4530513234100.

It is not a weakly prime, because it can be changed into another prime (4530513234133) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2265256617065 + 2265256617066.

It is an arithmetic number, because the mean of its divisors is an integer number (2265256617066).

Almost surely, 24530513234131 is an apocalyptic number.

4530513234131 is a deficient number, since it is larger than the sum of its proper divisors (1).

4530513234131 is an equidigital number, since it uses as much as digits as its factorization.

4530513234131 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 64800, while the sum is 35.

Adding to 4530513234131 its reverse (1314323150354), we get a palindrome (5844836384485).

The spelling of 4530513234131 in words is "four trillion, five hundred thirty billion, five hundred thirteen million, two hundred thirty-four thousand, one hundred thirty-one".