Base | Representation |
---|---|
bin | 101010010001100010… |
… | …001001001111101011 |
3 | 11100011101202222020121 |
4 | 222101202021033223 |
5 | 1220430134220133 |
6 | 32504045304111 |
7 | 3164560566016 |
oct | 522142111753 |
9 | 140141688217 |
10 | 45391320043 |
11 | 18283242643 |
12 | 8969565037 |
13 | 4385003974 |
14 | 22a861437d |
15 | 12a9e8a02d |
hex | a918893eb |
45391320043 has 2 divisors, whose sum is σ = 45391320044. Its totient is φ = 45391320042.
The previous prime is 45391319993. The next prime is 45391320059. The reversal of 45391320043 is 34002319354.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 45391320043 - 213 = 45391311851 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 45391319990 and 45391320008.
It is not a weakly prime, because it can be changed into another prime (45391320643) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 22695660021 + 22695660022.
It is an arithmetic number, because the mean of its divisors is an integer number (22695660022).
Almost surely, 245391320043 is an apocalyptic number.
45391320043 is a deficient number, since it is larger than the sum of its proper divisors (1).
45391320043 is an equidigital number, since it uses as much as digits as its factorization.
45391320043 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 38880, while the sum is 34.
Adding to 45391320043 its reverse (34002319354), we get a palindrome (79393639397).
The spelling of 45391320043 in words is "forty-five billion, three hundred ninety-one million, three hundred twenty thousand, forty-three".
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