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45401345333 is a prime number
BaseRepresentation
bin101010010010001000…
…011000110100110101
311100012002122022100122
4222102020120310311
51220440221022313
632505044221325
73165042032201
oct522210306465
9140162568318
1045401345333
111828896a803
12897099a845
134387103ba6
1422a9aa3b01
1512aacba708
hexa92218d35

45401345333 has 2 divisors, whose sum is σ = 45401345334. Its totient is φ = 45401345332.

The previous prime is 45401345309. The next prime is 45401345347. The reversal of 45401345333 is 33354310454.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 45378372484 + 22972849 = 213022^2 + 4793^2 .

It is a cyclic number.

It is not a de Polignac number, because 45401345333 - 216 = 45401279797 is a prime.

It is a super-2 number, since 2×454013453332 (a number of 22 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 45401345293 and 45401345302.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (45401345303) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 22700672666 + 22700672667.

It is an arithmetic number, because the mean of its divisors is an integer number (22700672667).

Almost surely, 245401345333 is an apocalyptic number.

It is an amenable number.

45401345333 is a deficient number, since it is larger than the sum of its proper divisors (1).

45401345333 is an equidigital number, since it uses as much as digits as its factorization.

45401345333 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 129600, while the sum is 35.

Adding to 45401345333 its reverse (33354310454), we get a palindrome (78755655787).

The spelling of 45401345333 in words is "forty-five billion, four hundred one million, three hundred forty-five thousand, three hundred thirty-three".