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45540241444301 is a prime number
BaseRepresentation
bin10100101101011001010011…
…11010100000110111001101
312222020121022201122000210012
422112230221322200313031
521432112403302204201
6240504521553523005
712410113431235352
oct1226545172406715
9188217281560705
1045540241444301
111356856507780a
125136006873465
131c545708973a6
14b36233742629
1553e915d4c5bb
hex296b29ea0dcd

45540241444301 has 2 divisors, whose sum is σ = 45540241444302. Its totient is φ = 45540241444300.

The previous prime is 45540241444273. The next prime is 45540241444319. The reversal of 45540241444301 is 10344414204554.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 31320924180100 + 14219317264201 = 5596510^2 + 3770851^2 .

It is a cyclic number.

It is not a de Polignac number, because 45540241444301 - 26 = 45540241444237 is a prime.

It is a super-3 number, since 3×455402414443013 (a number of 42 digits) contains 333 as substring.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (45540241434301) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 22770120722150 + 22770120722151.

It is an arithmetic number, because the mean of its divisors is an integer number (22770120722151).

Almost surely, 245540241444301 is an apocalyptic number.

It is an amenable number.

45540241444301 is a deficient number, since it is larger than the sum of its proper divisors (1).

45540241444301 is an equidigital number, since it uses as much as digits as its factorization.

45540241444301 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 614400, while the sum is 41.

Adding to 45540241444301 its reverse (10344414204554), we get a palindrome (55884655648855).

The spelling of 45540241444301 in words is "forty-five trillion, five hundred forty billion, two hundred forty-one million, four hundred forty-four thousand, three hundred one".