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45551024401 is a prime number
BaseRepresentation
bin101010011011000011…
…010111100100010001
311100120112021210102211
4222123003113210101
51221242030240101
632531552312121
73201540214261
oct523303274421
9140515253384
1045551024401
1118355402913
1289b2b42641
1343ac11c99c
1422c19077a1
1512b8ed4c51
hexa9b0d7911

45551024401 has 2 divisors, whose sum is σ = 45551024402. Its totient is φ = 45551024400.

The previous prime is 45551024353. The next prime is 45551024411. The reversal of 45551024401 is 10442015554.

It is a happy number.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 44379742225 + 1171282176 = 210665^2 + 34224^2 .

It is a cyclic number.

It is not a de Polignac number, because 45551024401 - 27 = 45551024273 is a prime.

It is not a weakly prime, because it can be changed into another prime (45551024411) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 22775512200 + 22775512201.

It is an arithmetic number, because the mean of its divisors is an integer number (22775512201).

Almost surely, 245551024401 is an apocalyptic number.

It is an amenable number.

45551024401 is a deficient number, since it is larger than the sum of its proper divisors (1).

45551024401 is an equidigital number, since it uses as much as digits as its factorization.

45551024401 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 16000, while the sum is 31.

Adding to 45551024401 its reverse (10442015554), we get a palindrome (55993039955).

The spelling of 45551024401 in words is "forty-five billion, five hundred fifty-one million, twenty-four thousand, four hundred one".