Base | Representation |
---|---|
bin | 1101010000100100010… |
… | …00100000101001010011 |
3 | 1121112220111202011122202 |
4 | 12220102020200221103 |
5 | 24431002103113011 |
6 | 545141502153415 |
7 | 44625316342313 |
oct | 6502210405123 |
9 | 1545814664582 |
10 | 455570754131 |
11 | 16622a8a5489 |
12 | 7436188286b |
13 | 33c6356588c |
14 | 1809a6c7443 |
15 | bcb538723b |
hex | 6a12220a53 |
455570754131 has 2 divisors, whose sum is σ = 455570754132. Its totient is φ = 455570754130.
The previous prime is 455570754113. The next prime is 455570754151. The reversal of 455570754131 is 131457075554.
Together with previous prime (455570754113) it forms an Ormiston pair, because they use the same digits, order apart.
It is a weak prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-455570754131 is a prime.
It is a super-2 number, since 2×4555707541312 (a number of 24 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (455570754151) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 227785377065 + 227785377066.
It is an arithmetic number, because the mean of its divisors is an integer number (227785377066).
Almost surely, 2455570754131 is an apocalyptic number.
455570754131 is a deficient number, since it is larger than the sum of its proper divisors (1).
455570754131 is an equidigital number, since it uses as much as digits as its factorization.
455570754131 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 1470000, while the sum is 47.
The spelling of 455570754131 in words is "four hundred fifty-five billion, five hundred seventy million, seven hundred fifty-four thousand, one hundred thirty-one".
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