Base | Representation |
---|---|
bin | 10101000111111010011110… |
… | …11111101011100111011111 |
3 | 20002110201012021122002011111 |
4 | 22203331033133223213133 |
5 | 22042024434140331143 |
6 | 242443251511202451 |
7 | 12533001055615666 |
oct | 1243751737534737 |
9 | 202421167562144 |
10 | 46451405011423 |
11 | 13889a26163835 |
12 | 5262715676427 |
13 | 1cbc46c11a0c9 |
14 | b6838d615ddd |
15 | 55849347799d |
hex | 2a3f4f7eb9df |
46451405011423 has 2 divisors, whose sum is σ = 46451405011424. Its totient is φ = 46451405011422.
The previous prime is 46451405011397. The next prime is 46451405011433. The reversal of 46451405011423 is 32411050415464.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 46451405011423 - 213 = 46451405003231 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (46451405011433) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 23225702505711 + 23225702505712.
It is an arithmetic number, because the mean of its divisors is an integer number (23225702505712).
Almost surely, 246451405011423 is an apocalyptic number.
46451405011423 is a deficient number, since it is larger than the sum of its proper divisors (1).
46451405011423 is an equidigital number, since it uses as much as digits as its factorization.
46451405011423 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 230400, while the sum is 40.
Adding to 46451405011423 its reverse (32411050415464), we get a palindrome (78862455426887).
The spelling of 46451405011423 in words is "forty-six trillion, four hundred fifty-one billion, four hundred five million, eleven thousand, four hundred twenty-three".
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