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4650969548131 is a prime number
BaseRepresentation
bin100001110101110001101…
…1000110100010101100011
3121110121222001202002001021
41003223203120310111203
51102200141201020011
613520343110350311
7660010234604614
oct103534330642543
917417861662037
104650969548131
111533513072065
1263148035b397
1327977a33027a
141211729b5c0b
1580eb0886471
hex43ae3634563

4650969548131 has 2 divisors, whose sum is σ = 4650969548132. Its totient is φ = 4650969548130.

The previous prime is 4650969548111. The next prime is 4650969548167. The reversal of 4650969548131 is 1318459690564.

It is a happy number.

4650969548131 is digitally balanced in base 3, because in such base it contains all the possibile digits an equal number of times.

It is a weak prime.

It is a cyclic number.

It is not a de Polignac number, because 4650969548131 - 221 = 4650967450979 is a prime.

It is a super-2 number, since 2×46509695481312 (a number of 26 digits) contains 22 as substring.

It is a self number, because there is not a number n which added to its sum of digits gives 4650969548131.

It is not a weakly prime, because it can be changed into another prime (4650969548111) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2325484774065 + 2325484774066.

It is an arithmetic number, because the mean of its divisors is an integer number (2325484774066).

Almost surely, 24650969548131 is an apocalyptic number.

4650969548131 is a deficient number, since it is larger than the sum of its proper divisors (1).

4650969548131 is an equidigital number, since it uses as much as digits as its factorization.

4650969548131 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 27993600, while the sum is 61.

The spelling of 4650969548131 in words is "four trillion, six hundred fifty billion, nine hundred sixty-nine million, five hundred forty-eight thousand, one hundred thirty-one".