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46512440653433 is a prime number
BaseRepresentation
bin10101001001101100001011…
…00000001011011001111001
320002200112201221221221200012
422210312011200023121321
522044024434301402213
6242531304212551305
712540261432202106
oct1244660540133171
9202615657857605
1046512440653433
11139028a7198a87
12527250a322535
131cc51482b3501
14b6b2dd853aad
15559d66a9c4a8
hex2a4d8580b679

46512440653433 has 2 divisors, whose sum is σ = 46512440653434. Its totient is φ = 46512440653432.

The previous prime is 46512440653409. The next prime is 46512440653457. The reversal of 46512440653433 is 33435604421564.

It is a balanced prime because it is at equal distance from previous prime (46512440653409) and next prime (46512440653457).

It can be written as a sum of positive squares in only one way, i.e., 38044125312064 + 8468315341369 = 6167992^2 + 2910037^2 .

It is a cyclic number.

It is not a de Polignac number, because 46512440653433 - 214 = 46512440637049 is a prime.

It is not a weakly prime, because it can be changed into another prime (46512445653433) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 23256220326716 + 23256220326717.

It is an arithmetic number, because the mean of its divisors is an integer number (23256220326717).

Almost surely, 246512440653433 is an apocalyptic number.

It is an amenable number.

46512440653433 is a deficient number, since it is larger than the sum of its proper divisors (1).

46512440653433 is an equidigital number, since it uses as much as digits as its factorization.

46512440653433 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 12441600, while the sum is 50.

The spelling of 46512440653433 in words is "forty-six trillion, five hundred twelve billion, four hundred forty million, six hundred fifty-three thousand, four hundred thirty-three".