Base | Representation |
---|---|
bin | 100001111011100001001… |
… | …1101110110001001011111 |
3 | 121111210210112122122021111 |
4 | 1003313002131312021133 |
5 | 1102400420320320111 |
6 | 13530142540242451 |
7 | 660624655001002 |
oct | 103670235661137 |
9 | 17453715578244 |
10 | 4663302120031 |
11 | 1538771524945 |
12 | 633942540427 |
13 | 27a9943583a9 |
14 | 1219c2845539 |
15 | 814833eba21 |
hex | 43dc277625f |
4663302120031 has 2 divisors, whose sum is σ = 4663302120032. Its totient is φ = 4663302120030.
The previous prime is 4663302119891. The next prime is 4663302120073. The reversal of 4663302120031 is 1300212033664.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 4663302120031 - 29 = 4663302119519 is a prime.
It is a super-3 number, since 3×46633021200313 (a number of 39 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.
It is a junction number, because it is equal to n+sod(n) for n = 4663302119975 and 4663302120002.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (4663302120131) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2331651060015 + 2331651060016.
It is an arithmetic number, because the mean of its divisors is an integer number (2331651060016).
Almost surely, 24663302120031 is an apocalyptic number.
4663302120031 is a deficient number, since it is larger than the sum of its proper divisors (1).
4663302120031 is an equidigital number, since it uses as much as digits as its factorization.
4663302120031 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 15552, while the sum is 31.
Adding to 4663302120031 its reverse (1300212033664), we get a palindrome (5963514153695).
The spelling of 4663302120031 in words is "four trillion, six hundred sixty-three billion, three hundred two million, one hundred twenty thousand, thirty-one".
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