Base | Representation |
---|---|
bin | 101011100011100010… |
… | …011001111100000011 |
3 | 11110201021120212011102 |
4 | 223203202121330003 |
5 | 1231234340321011 |
6 | 33252353405015 |
7 | 3243634651004 |
oct | 534342317403 |
9 | 143637525142 |
10 | 46767120131 |
11 | 18919902606 |
12 | 909226976b |
13 | 454405b464 |
14 | 23992271ab |
15 | 133ab4e73b |
hex | ae3899f03 |
46767120131 has 2 divisors, whose sum is σ = 46767120132. Its totient is φ = 46767120130.
The previous prime is 46767120121. The next prime is 46767120137. The reversal of 46767120131 is 13102176764.
46767120131 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a strong prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-46767120131 is a prime.
It is a super-2 number, since 2×467671201312 (a number of 22 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (46767120137) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 23383560065 + 23383560066.
It is an arithmetic number, because the mean of its divisors is an integer number (23383560066).
Almost surely, 246767120131 is an apocalyptic number.
46767120131 is a deficient number, since it is larger than the sum of its proper divisors (1).
46767120131 is an equidigital number, since it uses as much as digits as its factorization.
46767120131 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 42336, while the sum is 38.
Adding to 46767120131 its reverse (13102176764), we get a palindrome (59869296895).
The spelling of 46767120131 in words is "forty-six billion, seven hundred sixty-seven million, one hundred twenty thousand, one hundred thirty-one".
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