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4678001400113 is a prime number
BaseRepresentation
bin100010000010010111010…
…0111001001100100110001
3121120012201221221102210022
41010010232213021210301
51103121021324300423
613541013313013225
7661655143551656
oct104045647114461
917505657842708
104678001400113
111543a249205a8
12636765254215
1327c1977b3a62
141225b8b49c2d
1581a43b0ddc8
hex4412e9c9931

4678001400113 has 2 divisors, whose sum is σ = 4678001400114. Its totient is φ = 4678001400112.

The previous prime is 4678001400097. The next prime is 4678001400119. The reversal of 4678001400113 is 3110041008764.

It is a happy number.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 3465342340849 + 1212659059264 = 1861543^2 + 1101208^2 .

It is a cyclic number.

It is not a de Polignac number, because 4678001400113 - 24 = 4678001400097 is a prime.

It is a Sophie Germain prime.

It is a Curzon number.

It is not a weakly prime, because it can be changed into another prime (4678001400119) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2339000700056 + 2339000700057.

It is an arithmetic number, because the mean of its divisors is an integer number (2339000700057).

Almost surely, 24678001400113 is an apocalyptic number.

It is an amenable number.

4678001400113 is a deficient number, since it is larger than the sum of its proper divisors (1).

4678001400113 is an equidigital number, since it uses as much as digits as its factorization.

4678001400113 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 16128, while the sum is 35.

Adding to 4678001400113 its reverse (3110041008764), we get a palindrome (7788042408877).

The spelling of 4678001400113 in words is "four trillion, six hundred seventy-eight billion, one million, four hundred thousand, one hundred thirteen".