Base | Representation |
---|---|
bin | 100010000010010111010… |
… | …0111001001100100110001 |
3 | 121120012201221221102210022 |
4 | 1010010232213021210301 |
5 | 1103121021324300423 |
6 | 13541013313013225 |
7 | 661655143551656 |
oct | 104045647114461 |
9 | 17505657842708 |
10 | 4678001400113 |
11 | 1543a249205a8 |
12 | 636765254215 |
13 | 27c1977b3a62 |
14 | 1225b8b49c2d |
15 | 81a43b0ddc8 |
hex | 4412e9c9931 |
4678001400113 has 2 divisors, whose sum is σ = 4678001400114. Its totient is φ = 4678001400112.
The previous prime is 4678001400097. The next prime is 4678001400119. The reversal of 4678001400113 is 3110041008764.
It is a happy number.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 3465342340849 + 1212659059264 = 1861543^2 + 1101208^2 .
It is a cyclic number.
It is not a de Polignac number, because 4678001400113 - 24 = 4678001400097 is a prime.
It is a Sophie Germain prime.
It is a Curzon number.
It is not a weakly prime, because it can be changed into another prime (4678001400119) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2339000700056 + 2339000700057.
It is an arithmetic number, because the mean of its divisors is an integer number (2339000700057).
Almost surely, 24678001400113 is an apocalyptic number.
It is an amenable number.
4678001400113 is a deficient number, since it is larger than the sum of its proper divisors (1).
4678001400113 is an equidigital number, since it uses as much as digits as its factorization.
4678001400113 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 16128, while the sum is 35.
Adding to 4678001400113 its reverse (3110041008764), we get a palindrome (7788042408877).
The spelling of 4678001400113 in words is "four trillion, six hundred seventy-eight billion, one million, four hundred thousand, one hundred thirteen".
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