Base | Representation |
---|---|
bin | 1101101011100010011… |
… | …11011100100110111011 |
3 | 1122221021200110121222012 |
4 | 12311301033130212323 |
5 | 30200131113410021 |
6 | 555534422520135 |
7 | 45650211132353 |
oct | 6656117344673 |
9 | 1587250417865 |
10 | 470051310011 |
11 | 17139078a438 |
12 | 7712329604b |
13 | 354305ac43a |
14 | 18a71933b63 |
15 | c36179235b |
hex | 6d713dc9bb |
470051310011 has 2 divisors, whose sum is σ = 470051310012. Its totient is φ = 470051310010.
The previous prime is 470051310007. The next prime is 470051310049. The reversal of 470051310011 is 110013150074.
It is a happy number.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 470051310011 - 22 = 470051310007 is a prime.
It is not a weakly prime, because it can be changed into another prime (470051330011) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 235025655005 + 235025655006.
It is an arithmetic number, because the mean of its divisors is an integer number (235025655006).
Almost surely, 2470051310011 is an apocalyptic number.
470051310011 is a deficient number, since it is larger than the sum of its proper divisors (1).
470051310011 is an equidigital number, since it uses as much as digits as its factorization.
470051310011 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 420, while the sum is 23.
Adding to 470051310011 its reverse (110013150074), we get a palindrome (580064460085).
The spelling of 470051310011 in words is "four hundred seventy billion, fifty-one million, three hundred ten thousand, eleven".
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