Base | Representation |
---|---|
bin | 101011110011111110… |
… | …110100100001100001 |
3 | 11111102111201020101111 |
4 | 223303332310201201 |
5 | 1232321002121023 |
6 | 33340010503321 |
7 | 3253524640441 |
oct | 536376644141 |
9 | 144374636344 |
10 | 47043004513 |
11 | 18a5060562a |
12 | 914a734b41 |
13 | 458926475b |
14 | 23c3b20121 |
15 | 1354e9800d |
hex | af3fb4861 |
47043004513 has 2 divisors, whose sum is σ = 47043004514. Its totient is φ = 47043004512.
The previous prime is 47043004511. The next prime is 47043004573. The reversal of 47043004513 is 31540034074.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 44410083169 + 2632921344 = 210737^2 + 51312^2 .
It is a cyclic number.
It is not a de Polignac number, because 47043004513 - 21 = 47043004511 is a prime.
It is a super-2 number, since 2×470430045132 (a number of 22 digits) contains 22 as substring.
Together with 47043004511, it forms a pair of twin primes.
It is not a weakly prime, because it can be changed into another prime (47043004511) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 23521502256 + 23521502257.
It is an arithmetic number, because the mean of its divisors is an integer number (23521502257).
Almost surely, 247043004513 is an apocalyptic number.
It is an amenable number.
47043004513 is a deficient number, since it is larger than the sum of its proper divisors (1).
47043004513 is an equidigital number, since it uses as much as digits as its factorization.
47043004513 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 20160, while the sum is 31.
Adding to 47043004513 its reverse (31540034074), we get a palindrome (78583038587).
The spelling of 47043004513 in words is "forty-seven billion, forty-three million, four thousand, five hundred thirteen".
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