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47115121 is a prime number
BaseRepresentation
bin1011001110111…
…0101101110001
310021122200210111
42303232231301
544030140441
64401501321
71111320604
oct263565561
9107580714
1047115121
1124660319
1213941841
1399b8291
14638633b
15420a081
hex2ceeb71

47115121 has 2 divisors, whose sum is σ = 47115122. Its totient is φ = 47115120.

The previous prime is 47115091. The next prime is 47115151. The reversal of 47115121 is 12151174.

It is a balanced prime because it is at equal distance from previous prime (47115091) and next prime (47115151).

It can be written as a sum of positive squares in only one way, i.e., 47114496 + 625 = 6864^2 + 25^2 .

It is a cyclic number.

It is not a de Polignac number, because 47115121 - 215 = 47082353 is a prime.

It is a super-3 number, since 3×471151213 (a number of 24 digits) contains 333 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 47115092 and 47115101.

It is not a weakly prime, because it can be changed into another prime (47115151) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 23557560 + 23557561.

It is an arithmetic number, because the mean of its divisors is an integer number (23557561).

Almost surely, 247115121 is an apocalyptic number.

It is an amenable number.

47115121 is a deficient number, since it is larger than the sum of its proper divisors (1).

47115121 is an equidigital number, since it uses as much as digits as its factorization.

47115121 is an evil number, because the sum of its binary digits is even.

The product of its digits is 280, while the sum is 22.

The square root of 47115121 is about 6864.0455272383. The cubic root of 47115121 is about 361.1770143457.

Adding to 47115121 its reverse (12151174), we get a palindrome (59266295).

The spelling of 47115121 in words is "forty-seven million, one hundred fifteen thousand, one hundred twenty-one".