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47116256053 is a prime number
BaseRepresentation
bin101011111000010110…
…010000001100110101
311111121121112210121111
4223320112100030311
51232443230143203
633351144515021
73255404365666
oct537026201465
9144547483544
1047116256053
1118a88997599
12916b17ba71
13459b4a1269
1423cd74b36d
15135b61726d
hexaf8590335

47116256053 has 2 divisors, whose sum is σ = 47116256054. Its totient is φ = 47116256052.

The previous prime is 47116256021. The next prime is 47116256081. The reversal of 47116256053 is 35065261174.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 47053418724 + 62837329 = 216918^2 + 7927^2 .

It is a cyclic number.

It is not a de Polignac number, because 47116256053 - 25 = 47116256021 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 47116255997 and 47116256015.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (47116256093) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 23558128026 + 23558128027.

It is an arithmetic number, because the mean of its divisors is an integer number (23558128027).

Almost surely, 247116256053 is an apocalyptic number.

It is an amenable number.

47116256053 is a deficient number, since it is larger than the sum of its proper divisors (1).

47116256053 is an equidigital number, since it uses as much as digits as its factorization.

47116256053 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 151200, while the sum is 40.

The spelling of 47116256053 in words is "forty-seven billion, one hundred sixteen million, two hundred fifty-six thousand, fifty-three".