Base | Representation |
---|---|
bin | 100010010010001100001… |
… | …0100011100001110011111 |
3 | 121200110110111002200002112 |
4 | 1010210120110130032133 |
5 | 1104200122201313031 |
6 | 14004353525144235 |
7 | 664300301543204 |
oct | 104443024341637 |
9 | 17613414080075 |
10 | 4711987135391 |
11 | 1557384995528 |
12 | 64126ab5b07b |
13 | 2824528447a3 |
14 | 1240c0673cab |
15 | 828825e162b |
hex | 4491851c39f |
4711987135391 has 2 divisors, whose sum is σ = 4711987135392. Its totient is φ = 4711987135390.
The previous prime is 4711987135381. The next prime is 4711987135417. The reversal of 4711987135391 is 1935317891174.
It is a weak prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-4711987135391 is a prime.
It is a self number, because there is not a number n which added to its sum of digits gives 4711987135391.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (4711987135381) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2355993567695 + 2355993567696.
It is an arithmetic number, because the mean of its divisors is an integer number (2355993567696).
Almost surely, 24711987135391 is an apocalyptic number.
4711987135391 is a deficient number, since it is larger than the sum of its proper divisors (1).
4711987135391 is an equidigital number, since it uses as much as digits as its factorization.
4711987135391 is an odious number, because the sum of its binary digits is odd.
The product of its digits is 5715360, while the sum is 59.
The spelling of 4711987135391 in words is "four trillion, seven hundred eleven billion, nine hundred eighty-seven million, one hundred thirty-five thousand, three hundred ninety-one".
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