Base | Representation |
---|---|
bin | 1011001111001… |
… | …1010110010111 |
3 | 10021200122211112 |
4 | 2303303112113 |
5 | 44031242403 |
6 | 4402125235 |
7 | 1111430132 |
oct | 263632627 |
9 | 107618745 |
10 | 47134103 |
11 | 24673605 |
12 | 1395081b |
13 | 99c3b03 |
14 | 638d219 |
15 | 42109d8 |
hex | 2cf3597 |
47134103 has 2 divisors, whose sum is σ = 47134104. Its totient is φ = 47134102.
The previous prime is 47134067. The next prime is 47134111. The reversal of 47134103 is 30143174.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 47134103 - 26 = 47134039 is a prime.
It is a super-2 number, since 2×471341032 = 4443247331229218, which contains 22 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (47134163) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 23567051 + 23567052.
It is an arithmetic number, because the mean of its divisors is an integer number (23567052).
Almost surely, 247134103 is an apocalyptic number.
47134103 is a deficient number, since it is larger than the sum of its proper divisors (1).
47134103 is an equidigital number, since it uses as much as digits as its factorization.
47134103 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 1008, while the sum is 23.
The square root of 47134103 is about 6865.4281002717. The cubic root of 47134103 is about 361.2255121630.
Adding to 47134103 its reverse (30143174), we get a palindrome (77277277).
The spelling of 47134103 in words is "forty-seven million, one hundred thirty-four thousand, one hundred three".
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