Base | Representation |
---|---|
bin | 100010010011100111101… |
… | …0110000010100100000101 |
3 | 121200202101111001211121021 |
4 | 1010213033112002210011 |
5 | 1104222414243110333 |
6 | 14010022335551141 |
7 | 664436345616535 |
oct | 104471726024405 |
9 | 17622344054537 |
10 | 4715057785093 |
11 | 1558710220057 |
12 | 64198738b4b1 |
13 | 282821a64486 |
14 | 1242d23cb4c5 |
15 | 829b1e8d82d |
hex | 449cf582905 |
4715057785093 has 2 divisors, whose sum is σ = 4715057785094. Its totient is φ = 4715057785092.
The previous prime is 4715057785079. The next prime is 4715057785127. The reversal of 4715057785093 is 3905877505174.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 2615523438564 + 2099534346529 = 1617258^2 + 1448977^2 .
It is a cyclic number.
It is not a de Polignac number, because 4715057785093 - 29 = 4715057784581 is a prime.
It is a super-3 number, since 3×47150577850933 (a number of 39 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (4715057785003) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2357528892546 + 2357528892547.
It is an arithmetic number, because the mean of its divisors is an integer number (2357528892547).
Almost surely, 24715057785093 is an apocalyptic number.
It is an amenable number.
4715057785093 is a deficient number, since it is larger than the sum of its proper divisors (1).
4715057785093 is an equidigital number, since it uses as much as digits as its factorization.
4715057785093 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 37044000, while the sum is 61.
The spelling of 4715057785093 in words is "four trillion, seven hundred fifteen billion, fifty-seven million, seven hundred eighty-five thousand, ninety-three".
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