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47157676761553 is a prime number
BaseRepresentation
bin10101011100011110000001…
…00100100110000111010001
320011222020012120112101200021
422232033000210212013101
522140112410222332203
6244143534310023441
712635013122501221
oct1256170044460721
9204866176471607
1047157676761553
11140315051520a6
125357582647b81
132040c46a3c3a7
14b9062d868081
1556ba2ce465bd
hex2ae3c09261d1

47157676761553 has 2 divisors, whose sum is σ = 47157676761554. Its totient is φ = 47157676761552.

The previous prime is 47157676761529. The next prime is 47157676761623. The reversal of 47157676761553 is 35516767675174.

It is an a-pointer prime, because the next prime (47157676761623) can be obtained adding 47157676761553 to its sum of digits (70).

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 46493210499649 + 664466261904 = 6818593^2 + 815148^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-47157676761553 is a prime.

It is not a weakly prime, because it can be changed into another prime (47157616761553) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 23578838380776 + 23578838380777.

It is an arithmetic number, because the mean of its divisors is an integer number (23578838380777).

Almost surely, 247157676761553 is an apocalyptic number.

It is an amenable number.

47157676761553 is a deficient number, since it is larger than the sum of its proper divisors (1).

47157676761553 is an equidigital number, since it uses as much as digits as its factorization.

47157676761553 is an evil number, because the sum of its binary digits is even.

The product of its digits is 777924000, while the sum is 70.

The spelling of 47157676761553 in words is "forty-seven trillion, one hundred fifty-seven billion, six hundred seventy-six million, seven hundred sixty-one thousand, five hundred fifty-three".