Base | Representation |
---|---|
bin | 100010011010111000001… |
… | …0100000101101001100111 |
3 | 121202020121122222101111111 |
4 | 1010311300110011221213 |
5 | 1110001324141311421 |
6 | 14021121051445451 |
7 | 665530515435331 |
oct | 104656024055147 |
9 | 17666548871444 |
10 | 4730643307111 |
11 | 1564288901467 |
12 | 6449b6a56887 |
13 | 2841369aa257 |
14 | 124d702aa451 |
15 | 830c53b0ee1 |
hex | 44d70505a67 |
4730643307111 has 2 divisors, whose sum is σ = 4730643307112. Its totient is φ = 4730643307110.
The previous prime is 4730643307069. The next prime is 4730643307127. The reversal of 4730643307111 is 1117033460374.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 4730643307111 - 241 = 2531620051559 is a prime.
It is a super-2 number, since 2×47306433071112 (a number of 26 digits) contains 22 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (4730643307141) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2365321653555 + 2365321653556.
It is an arithmetic number, because the mean of its divisors is an integer number (2365321653556).
Almost surely, 24730643307111 is an apocalyptic number.
4730643307111 is a deficient number, since it is larger than the sum of its proper divisors (1).
4730643307111 is an equidigital number, since it uses as much as digits as its factorization.
4730643307111 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 127008, while the sum is 40.
Adding to 4730643307111 its reverse (1117033460374), we get a palindrome (5847676767485).
The spelling of 4730643307111 in words is "four trillion, seven hundred thirty billion, six hundred forty-three million, three hundred seven thousand, one hundred eleven".
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