Base | Representation |
---|---|
bin | 1101110001010001101… |
… | …01101010000010010011 |
3 | 1200020020100111101111102 |
4 | 12320220311222002103 |
5 | 30222433134311021 |
6 | 1001204215135015 |
7 | 46116432610331 |
oct | 6705065520223 |
9 | 1606210441442 |
10 | 473131557011 |
11 | 17272147a613 |
12 | 7784297446b |
13 | 358017ac5b9 |
14 | 18c84a68b51 |
15 | c491dd800b |
hex | 6e28d6a093 |
473131557011 has 2 divisors, whose sum is σ = 473131557012. Its totient is φ = 473131557010.
The previous prime is 473131556951. The next prime is 473131557113. The reversal of 473131557011 is 110755131374.
It is a weak prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-473131557011 is a prime.
It is not a weakly prime, because it can be changed into another prime (473134557011) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 236565778505 + 236565778506.
It is an arithmetic number, because the mean of its divisors is an integer number (236565778506).
Almost surely, 2473131557011 is an apocalyptic number.
473131557011 is a deficient number, since it is larger than the sum of its proper divisors (1).
473131557011 is an equidigital number, since it uses as much as digits as its factorization.
473131557011 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 44100, while the sum is 38.
Adding to 473131557011 its reverse (110755131374), we get a palindrome (583886688385).
The spelling of 473131557011 in words is "four hundred seventy-three billion, one hundred thirty-one million, five hundred fifty-seven thousand, eleven".
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