Base | Representation |
---|---|
bin | 101100000101000111… |
… | …001001101110110001 |
3 | 11112011112111111112021 |
4 | 230011013021232301 |
5 | 1233413040314301 |
6 | 33424314431441 |
7 | 3263614525606 |
oct | 540507115661 |
9 | 145145444467 |
10 | 47330401201 |
11 | 19088860a56 |
12 | 920aa32581 |
13 | 460396ba75 |
14 | 240dd726ad |
15 | 13703178a1 |
hex | b051c9bb1 |
47330401201 has 2 divisors, whose sum is σ = 47330401202. Its totient is φ = 47330401200.
The previous prime is 47330401169. The next prime is 47330401241. The reversal of 47330401201 is 10210403374.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 40240761201 + 7089640000 = 200601^2 + 84200^2 .
It is a cyclic number.
It is not a de Polignac number, because 47330401201 - 25 = 47330401169 is a prime.
It is not a weakly prime, because it can be changed into another prime (47330401241) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 23665200600 + 23665200601.
It is an arithmetic number, because the mean of its divisors is an integer number (23665200601).
Almost surely, 247330401201 is an apocalyptic number.
It is an amenable number.
47330401201 is a deficient number, since it is larger than the sum of its proper divisors (1).
47330401201 is an equidigital number, since it uses as much as digits as its factorization.
47330401201 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 2016, while the sum is 25.
Adding to 47330401201 its reverse (10210403374), we get a palindrome (57540804575).
The spelling of 47330401201 in words is "forty-seven billion, three hundred thirty million, four hundred one thousand, two hundred one".
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