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4747780113437 is a prime number
BaseRepresentation
bin100010100010110110110…
…1111110100010000011101
3121210212211221220100102002
41011011231233310100131
51110241423202112222
614033033341012045
71000005263045654
oct105055557642035
917725757810362
104747780113437
111570582110719
12648199b54025
1328593813013a
14125b181dc19b
1583779aad392
hex4516dbf441d

4747780113437 has 2 divisors, whose sum is σ = 4747780113438. Its totient is φ = 4747780113436.

The previous prime is 4747780113407. The next prime is 4747780113481. The reversal of 4747780113437 is 7343110877474.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 3192157528921 + 1555622584516 = 1786661^2 + 1247246^2 .

It is a cyclic number.

It is not a de Polignac number, because 4747780113437 - 218 = 4747779851293 is a prime.

It is a super-3 number, since 3×47477801134373 (a number of 39 digits) contains 333 as substring.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (4747780113407) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2373890056718 + 2373890056719.

It is an arithmetic number, because the mean of its divisors is an integer number (2373890056719).

Almost surely, 24747780113437 is an apocalyptic number.

It is an amenable number.

4747780113437 is a deficient number, since it is larger than the sum of its proper divisors (1).

4747780113437 is an equidigital number, since it uses as much as digits as its factorization.

4747780113437 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 11063808, while the sum is 56.

The spelling of 4747780113437 in words is "four trillion, seven hundred forty-seven billion, seven hundred eighty million, one hundred thirteen thousand, four hundred thirty-seven".