Base | Representation |
---|---|
bin | 10101100110000000111000… |
… | …10100111000100101111111 |
3 | 20020010120201110022002011011 |
4 | 22303000130110320211333 |
5 | 22211001034204130221 |
6 | 244554333212340051 |
7 | 13000503161241136 |
oct | 1263003424704577 |
9 | 206116643262134 |
10 | 47485633661311 |
11 | 141485a9287a2a |
12 | 53ab04a774627 |
13 | 2065b50878021 |
14 | ba246193a91d |
15 | 575324ba61e1 |
hex | 2b301c53897f |
47485633661311 has 2 divisors, whose sum is σ = 47485633661312. Its totient is φ = 47485633661310.
The previous prime is 47485633661293. The next prime is 47485633661381. The reversal of 47485633661311 is 11316633658474.
47485633661311 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a weak prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-47485633661311 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (47485633661381) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 23742816830655 + 23742816830656.
It is an arithmetic number, because the mean of its divisors is an integer number (23742816830656).
Almost surely, 247485633661311 is an apocalyptic number.
47485633661311 is a deficient number, since it is larger than the sum of its proper divisors (1).
47485633661311 is an equidigital number, since it uses as much as digits as its factorization.
47485633661311 is an odious number, because the sum of its binary digits is odd.
The product of its digits is 26127360, while the sum is 58.
The spelling of 47485633661311 in words is "forty-seven trillion, four hundred eighty-five billion, six hundred thirty-three million, six hundred sixty-one thousand, three hundred eleven".
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