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4786640140147 is a prime number
BaseRepresentation
bin100010110100111100111…
…1111000011011101110011
3121221121011011220020112121
41011221321333003131303
51111411014333441042
614102541354135111
71002552255606325
oct105517177033563
917847134806477
104786640140147
111586003631978
12653824121497
132894bbc77398
14127963223615
15847a1465367
hex45a79fc3773

4786640140147 has 2 divisors, whose sum is σ = 4786640140148. Its totient is φ = 4786640140146.

The previous prime is 4786640140129. The next prime is 4786640140199. The reversal of 4786640140147 is 7410410466874.

It is an a-pointer prime, because the next prime (4786640140199) can be obtained adding 4786640140147 to its sum of digits (52).

It is a weak prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-4786640140147 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 4786640140094 and 4786640140103.

It is not a weakly prime, because it can be changed into another prime (4786640144147) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2393320070073 + 2393320070074.

It is an arithmetic number, because the mean of its divisors is an integer number (2393320070074).

Almost surely, 24786640140147 is an apocalyptic number.

4786640140147 is a deficient number, since it is larger than the sum of its proper divisors (1).

4786640140147 is an equidigital number, since it uses as much as digits as its factorization.

4786640140147 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 3612672, while the sum is 52.

The spelling of 4786640140147 in words is "four trillion, seven hundred eighty-six billion, six hundred forty million, one hundred forty thousand, one hundred forty-seven".