Base | Representation |
---|---|
bin | 101100100111000000… |
… | …010000100101001001 |
3 | 11120122011110022022201 |
4 | 230213000100211021 |
5 | 1241044122111333 |
6 | 34000550120201 |
7 | 3313660643305 |
oct | 544700204511 |
9 | 146564408281 |
10 | 47899019593 |
11 | 1934a825407 |
12 | 9349350061 |
13 | 46946ca859 |
14 | 24656aad05 |
15 | 13a51d717d |
hex | b27010949 |
47899019593 has 2 divisors, whose sum is σ = 47899019594. Its totient is φ = 47899019592.
The previous prime is 47899019573. The next prime is 47899019639. The reversal of 47899019593 is 39591099874.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 30797442064 + 17101577529 = 175492^2 + 130773^2 .
It is a cyclic number.
It is not a de Polignac number, because 47899019593 - 25 = 47899019561 is a prime.
It is not a weakly prime, because it can be changed into another prime (47899019533) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (13) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 23949509796 + 23949509797.
It is an arithmetic number, because the mean of its divisors is an integer number (23949509797).
Almost surely, 247899019593 is an apocalyptic number.
It is an amenable number.
47899019593 is a deficient number, since it is larger than the sum of its proper divisors (1).
47899019593 is an equidigital number, since it uses as much as digits as its factorization.
47899019593 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 22044960, while the sum is 64.
The spelling of 47899019593 in words is "forty-seven billion, eight hundred ninety-nine million, nineteen thousand, five hundred ninety-three".
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