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47915213233 is a prime number
BaseRepresentation
bin101100100111111110…
…000010000110110001
311120200021221000211011
4230213332002012301
51241112243310413
634002325150521
73314245410136
oct544776020661
9146607830734
1047915213233
1119358985988
12935285b441
134697b7a5a4
1424678c458d
1513a683533d
hexb27f821b1

47915213233 has 2 divisors, whose sum is σ = 47915213234. Its totient is φ = 47915213232.

The previous prime is 47915213179. The next prime is 47915213261. The reversal of 47915213233 is 33231251974.

It is a happy number.

47915213233 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 33917483889 + 13997729344 = 184167^2 + 118312^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-47915213233 is a prime.

It is not a weakly prime, because it can be changed into another prime (47915213033) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 23957606616 + 23957606617.

It is an arithmetic number, because the mean of its divisors is an integer number (23957606617).

Almost surely, 247915213233 is an apocalyptic number.

It is an amenable number.

47915213233 is a deficient number, since it is larger than the sum of its proper divisors (1).

47915213233 is an equidigital number, since it uses as much as digits as its factorization.

47915213233 is an evil number, because the sum of its binary digits is even.

The product of its digits is 136080, while the sum is 40.

The spelling of 47915213233 in words is "forty-seven billion, nine hundred fifteen million, two hundred thirteen thousand, two hundred thirty-three".