Base | Representation |
---|---|
bin | 101100101010010110… |
… | …101001011011110101 |
3 | 11120210002012121002011 |
4 | 230222112221123311 |
5 | 1241203014021323 |
6 | 34010314444221 |
7 | 3315242434435 |
oct | 545226513365 |
9 | 146702177064 |
10 | 47955220213 |
11 | 193795207aa |
12 | 9364133671 |
13 | 46a3247364 |
14 | 246cd3a2c5 |
15 | 13aa0d920d |
hex | b2a5a96f5 |
47955220213 has 2 divisors, whose sum is σ = 47955220214. Its totient is φ = 47955220212.
The previous prime is 47955220177. The next prime is 47955220331. The reversal of 47955220213 is 31202255974.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 42435176004 + 5520044209 = 205998^2 + 74297^2 .
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-47955220213 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (47955220513) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 23977610106 + 23977610107.
It is an arithmetic number, because the mean of its divisors is an integer number (23977610107).
Almost surely, 247955220213 is an apocalyptic number.
It is an amenable number.
47955220213 is a deficient number, since it is larger than the sum of its proper divisors (1).
47955220213 is an equidigital number, since it uses as much as digits as its factorization.
47955220213 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 151200, while the sum is 40.
The spelling of 47955220213 in words is "forty-seven billion, nine hundred fifty-five million, two hundred twenty thousand, two hundred thirteen".
• e-mail: info -at- numbersaplenty.com • Privacy notice • done in 0.077 sec. • engine limits •