Base | Representation |
---|---|
bin | 100010111001111000010… |
… | …0110111000101110000101 |
3 | 121222121110112012101120021 |
4 | 1011303300212320232011 |
5 | 1112044201334243343 |
6 | 14111451302135141 |
7 | 1003405406065405 |
oct | 105636046705605 |
9 | 17877415171507 |
10 | 4797220227973 |
11 | 158a542834508 |
12 | 6558974214b1 |
13 | 28a4b6baac94 |
14 | 128288428805 |
15 | 84bc020b0ed |
hex | 45cf09b8b85 |
4797220227973 has 2 divisors, whose sum is σ = 4797220227974. Its totient is φ = 4797220227972.
The previous prime is 4797220227953. The next prime is 4797220228033. The reversal of 4797220227973 is 3797220227974.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 3393616099329 + 1403604128644 = 1842177^2 + 1184738^2 .
It is a cyclic number.
It is not a de Polignac number, because 4797220227973 - 217 = 4797220096901 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (4797220227953) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2398610113986 + 2398610113987.
It is an arithmetic number, because the mean of its divisors is an integer number (2398610113987).
Almost surely, 24797220227973 is an apocalyptic number.
It is an amenable number.
4797220227973 is a deficient number, since it is larger than the sum of its proper divisors (1).
4797220227973 is an equidigital number, since it uses as much as digits as its factorization.
4797220227973 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 37340352, while the sum is 61.
Subtracting from 4797220227973 its reverse (3797220227974), we obtain a palindrome (999999999999).
The spelling of 4797220227973 in words is "four trillion, seven hundred ninety-seven billion, two hundred twenty million, two hundred twenty-seven thousand, nine hundred seventy-three".
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