Search a number
-
+
4797751401349 is a prime number
BaseRepresentation
bin100010111010001000001…
…0001001001101110000101
3121222122211112200210110021
41011310100101021232011
51112101243324320344
614112020115055141
71003424516016004
oct105642021115605
917878745623407
104797751401349
11158a795652975
12655a052a14b1
1328a56cc5915a
141282d8bb6c3b
1584c01b80b84
hex45d10449b85

4797751401349 has 2 divisors, whose sum is σ = 4797751401350. Its totient is φ = 4797751401348.

The previous prime is 4797751401307. The next prime is 4797751401353. The reversal of 4797751401349 is 9431041577974.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 2458326089025 + 2339425312324 = 1567905^2 + 1529518^2 .

It is a cyclic number.

It is not a de Polignac number, because 4797751401349 - 219 = 4797750877061 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (4797751401389) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2398875700674 + 2398875700675.

It is an arithmetic number, because the mean of its divisors is an integer number (2398875700675).

Almost surely, 24797751401349 is an apocalyptic number.

It is an amenable number.

4797751401349 is a deficient number, since it is larger than the sum of its proper divisors (1).

4797751401349 is an equidigital number, since it uses as much as digits as its factorization.

4797751401349 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 26671680, while the sum is 61.

The spelling of 4797751401349 in words is "four trillion, seven hundred ninety-seven billion, seven hundred fifty-one million, four hundred one thousand, three hundred forty-nine".