Base | Representation |
---|---|
bin | 11100101001111… |
… | …011100100010111 |
3 | 1020111121211102121 |
4 | 130221323210113 |
5 | 1441033111233 |
6 | 115412120411 |
7 | 14625224665 |
oct | 3451734427 |
9 | 1214554377 |
10 | 480753943 |
11 | 22741160a |
12 | 115006107 |
13 | 787a6bb7 |
14 | 47bc5c35 |
15 | 2c31592d |
hex | 1ca7b917 |
480753943 has 2 divisors, whose sum is σ = 480753944. Its totient is φ = 480753942.
The previous prime is 480753907. The next prime is 480753971. The reversal of 480753943 is 349357084.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 480753943 - 29 = 480753431 is a prime.
It is a super-3 number, since 3×4807539433 (a number of 27 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.
It is a self number, because there is not a number n which added to its sum of digits gives 480753943.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (480753643) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 240376971 + 240376972.
It is an arithmetic number, because the mean of its divisors is an integer number (240376972).
Almost surely, 2480753943 is an apocalyptic number.
480753943 is a deficient number, since it is larger than the sum of its proper divisors (1).
480753943 is an equidigital number, since it uses as much as digits as its factorization.
480753943 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 362880, while the sum is 43.
The square root of 480753943 is about 21926.1018651287. The cubic root of 480753943 is about 783.3832564330.
The spelling of 480753943 in words is "four hundred eighty million, seven hundred fifty-three thousand, nine hundred forty-three".
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