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481000443433 is a prime number
BaseRepresentation
bin1101111111111011101…
…11000100111000101001
31200222112202012020101021
412333331313010320221
530340042103142213
61004545112452441
746515432211216
oct6777567047051
91628482166337
10481000443433
11175a9a235434
127927a0aa121
1336486b07103
14193cdb62b0d
15c7a2b34d8d
hex6ffddc4e29

481000443433 has 2 divisors, whose sum is σ = 481000443434. Its totient is φ = 481000443432.

The previous prime is 481000443419. The next prime is 481000443449. The reversal of 481000443433 is 334344000184.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 424305023769 + 56695419664 = 651387^2 + 238108^2 .

It is a cyclic number.

It is not a de Polignac number, because 481000443433 - 25 = 481000443401 is a prime.

It is a super-3 number, since 3×4810004434333 (a number of 36 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.

It is not a weakly prime, because it can be changed into another prime (481000443463) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 240500221716 + 240500221717.

It is an arithmetic number, because the mean of its divisors is an integer number (240500221717).

Almost surely, 2481000443433 is an apocalyptic number.

It is an amenable number.

481000443433 is a deficient number, since it is larger than the sum of its proper divisors (1).

481000443433 is an equidigital number, since it uses as much as digits as its factorization.

481000443433 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 55296, while the sum is 34.

The spelling of 481000443433 in words is "four hundred eighty-one billion, four hundred forty-three thousand, four hundred thirty-three".