Base | Representation |
---|---|
bin | 100011000000110110010… |
… | …0111010001000000100011 |
3 | 122001001002111012021021022 |
4 | 1012001230213101000203 |
5 | 1112320324003313011 |
6 | 14122404302120055 |
7 | 1004445305510603 |
oct | 106015447210043 |
9 | 18031074167238 |
10 | 4812185604131 |
11 | 1595922358084 |
12 | 65877328002b |
13 | 28ba304c3549 |
14 | 128ca7bd8c03 |
15 | 85298e818db |
hex | 4606c9d1023 |
4812185604131 has 2 divisors, whose sum is σ = 4812185604132. Its totient is φ = 4812185604130.
The previous prime is 4812185603993. The next prime is 4812185604133. The reversal of 4812185604131 is 1314065812184.
It is a strong prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-4812185604131 is a prime.
It is a super-2 number, since 2×48121856041312 (a number of 26 digits) contains 22 as substring.
Together with 4812185604133, it forms a pair of twin primes.
It is a Chen prime.
It is not a weakly prime, because it can be changed into another prime (4812185604133) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2406092802065 + 2406092802066.
It is an arithmetic number, because the mean of its divisors is an integer number (2406092802066).
Almost surely, 24812185604131 is an apocalyptic number.
4812185604131 is a deficient number, since it is larger than the sum of its proper divisors (1).
4812185604131 is an equidigital number, since it uses as much as digits as its factorization.
4812185604131 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 184320, while the sum is 44.
The spelling of 4812185604131 in words is "four trillion, eight hundred twelve billion, one hundred eighty-five million, six hundred four thousand, one hundred thirty-one".
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